Answer :

Given:- Rhombus OABC i.e all sides are equal

To Prove:- Diagonals are perpendicular bisector of each other

Proof:- Let, O at the origin

D is the point of intersection of both diagonals

be position vector of A and C respectively



as AB = OC




Tip:- Directions are important as sign of vector get changed

Magnitude are same AC = OB = √a2 + c2

Hence from two equations, diagonals are equal

Now let’s find position vector of mid-point of OB and AC


Magnitude is same AD = DC = OD = DB = 0.5(√a2 + c2)

Thus the position of mid-point is same, and it is the bisecting point D

By Dot Product of OB and AC vectors we get,

As the side of a rhombus are equal OA = OC

Hence OB is perpendicular on AC

Thus diagonals of rhombus bisect each other at 90°

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