Q. 424.3( 6 Votes )

A silver ornament of mass ‘m’ gram is polished with gold equivalent to 1% of the mass of silver. Compute the ratio of the number of atoms of gold and silver in the ornament.

Answer :

Mass of silver = ‘m’ g

Mass of gold = m/100 g


Number of atoms of silver(Ag) =


= {Atomic weight of Silver (Ag) = 108g/mole}


Number of atoms of gold(Au) =


=


Ratio of number of atoms of gold to silver = Au : Ag


= :


= 108 : 100 × 197


= 108 : 19700


= 1 : 182.41


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