Which of the foll A. 0.2 mole of sucrose (C₁₂H₂₂O₁₁)

B. 2 moles of CO₂

C. 2 moles of CaCO₃

D. 10 moles of H₂O

Mass of given sample = Molar mass X number of moles

m = M X N

(a) 0.2 moles of sucrose (C₁₂H₂₂O₁₁):

Molar mass of sucrose (C₁₂H₂₂O₁₁) = 342g/mole

Thus, the mass of 0.2 moles of sucrose (C₁₂H₂₂O₁₁) = 342 X 0.2

= 68.4g

(b) 2 moles of CO₂ = 2×44 = 88g

(c) 2 moles of CaCO₃ = 2×100 = 200 g

(d) 10 moles of H₂O = 10×18 = 180

Thus, the mass of 0.2 moles of sucrose (C₁₂H₂₂O₁₁) would weigh the highest.