# Give the chemical

(Aluminium fluoride a) Ammonia = NH3

The atomic mass of N = 14

The atomic mass of H = 1

Thus, Ratio by mass = N : H × 3

= 14 : 1 × 3

= 14:3

(b) Carbon monoxide = CO

The atomic mass of C = 12

The atomic mass of O = 16

Thus, Ratio by mass = C:O

= 12:16

= 3:6

(c) Hydrogen chloride = HCl

The atomic mass of H = 1

The atomic mass of Cl = 35.5

Thus, Ratio by mass = H : Cl

= 1:35.5

(d) Aluminium fluoride = AlF3

The atomic mass of Al = 27

The atomic mass of F = 19

Thus, Ratio by mass = Al : F × 3

= 27 : 19 × 3

= 27 : 57

= 9 : 19

(e) Magnesium sulphide = MgS

The atomic mass of Mg = 24

The atomic mass of S = 32

Thus, Ratio by mass = Mg : S

= 24 : 32

= 3 : 4

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation view all courses RELATED QUESTIONS :

What is meant by Lakhmir Singh & Manjit Kaur - Chemistry

Stat the chemicalLakhmir Singh & Manjit Kaur - Chemistry

Give two symbols Lakhmir Singh & Manjit Kaur - Chemistry

Explain the formaLakhmir Singh & Manjit Kaur - Chemistry

The atomicities oLakhmir Singh & Manjit Kaur - Chemistry

The law of constaLakhmir Singh & Manjit Kaur - Chemistry

In this crosswordNCERT Science - Exemplar