Answer :

Mass of the block m = 1kg
Angle of inclination = ![]()
Coefficient of friction = 0.1
Displacement = 10 m
a) Work done against gravity
= ![]()
b) Work done against friction
= ![]()
![]()
![]()
c) Vertical raise in height h ![]()
∴ change in P.E.![]()
d) Applying work energy theorem,
![]()
-(1)
![]()
![]()
Putting these in equation (1),
We get,
![]()
![]()
∴ there is a decrease in the kinetic energy by 41.3 J
e) Applied force F = ![]()
Displacement d = ![]()
Work done W by the force F is given as
= ![]()
=![]()
![]()
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