Q. 47

# Two identical steel cubes (masses 50g, side 1cm) collide head-on face to face with a speed of 10cm/s each. Find the maximum compression of each. Young’s modulus for steel = Y= 2 × 10^{11} N/m^{2}.

Answer :

From Hooke’s law, ,

Where F = Force,

A= Area of cross section

Y= young’s modulus

L=initial length of the cube

Δ L=change in length

Kinetic energy of both boxes K.E.

Now, the kinetic energy gets converted to potential energy due to compression and,

P.E.

Now, P.E = K.E

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