Given: h = 75 cm = 0.75 mSpecific gravity of mercury = 136Density of water = 103 kg/m3g = 9.8 m/s2Specific gravity is defined as the ratio of density of a substance w.r.t density of any other substance. Primarily the specific gravity is measured w.r.t waterDensity of mercury = 136 × 103 kg/m3 = 136 × 103 kg/m3 = ρPressure exerted by a liquid is given by the relationP = hρg= 0.75 × 136 × 103 × 9.8= 999600 Pa= 10 × 105 N/m2 (approx.)For CGS unitCGS unit of Force ⇒ dyne1 dyne = 10-5 N ⇒ 1 N = 105 dyne1 m = 100 cm10 × 105 N/m2 = 10 × 105 × 105 dyne / (100 cm)2= 10 × 106 dyne /cm2 (CGS)

Q. 104.1( 26 Votes )

The height of mer

Class 11th HC Verma - Concepts of Physics Part 1 1. Introduction to Physics

Answer :

Given: h = 75 cm = 0.75 m

Specific gravity of mercury = 136

Density of water = 10³ kg/m³

g = 9.8 m/s²

Specific gravity is defined as the ratio of density of a substance w.r.t density of any other substance. Primarily the specific gravity is measured w.r.t water