Answer :

**Given:** A manufacturer produces two products A and B

**To find:** the production level of A and B per day for maximum profit graphically

Let the number of units of products A and B to be produced each day be x and y respectively

Let z be a total profit of manufacture

Each unit of product A is sold at Rs. 7 profit and that of B at a profit of Rs. 4

∴ z = 7x + 4y

We need to maximize the cost

Hence, the mathematical formulation of LPP is

Maximize z = 7x + 4y

subject to the constraints,

3x + 2y 12

3x + y 9

x, y 0

The feasible region determined by the system of constraints is as follows:

The corner points of the enclosed region are A(0, 6) , B(2, 3), C(3, 0)

The value of z at these corners points is as follows:

Case 1: A(0, 6)

z = 7x + 4y

⇒ z = 7(0) + 4(6)

⇒ z = 0 + 24

⇒ z = 24

Case 2: B(2, 3)

z = 7x + 4y

⇒ z = 7(2) + 4(3)

⇒ z = 14 + 12

⇒ z = 26

Case 3: C(3, 0)

z = 7x + 4y

⇒ z = 7(3) + 4(0)

⇒ z = 21 + 0

⇒ z = 21

The value of z is maximum in the second case at point B(2, 3)

Hence, the unit of products A and B to be produced are **2 and 3** respectively, and the total maximum profit is **Rs. 26**

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