Answer :
Given: A manufacturer produces two products A and B
To find: the production level of A and B per day for maximum profit graphically
Let the number of units of products A and B to be produced each day be x and y respectively
Let z be a total profit of manufacture
Each unit of product A is sold at Rs. 7 profit and that of B at a profit of Rs. 4
∴ z = 7x + 4y
We need to maximize the cost
Hence, the mathematical formulation of LPP is
Maximize z = 7x + 4y
subject to the constraints,
3x + 2y 12
3x + y 9
x, y 0
The feasible region determined by the system of constraints is as follows:
The corner points of the enclosed region are A(0, 6) , B(2, 3), C(3, 0)
The value of z at these corners points is as follows:
Case 1: A(0, 6)
z = 7x + 4y
⇒ z = 7(0) + 4(6)
⇒ z = 0 + 24
⇒ z = 24
Case 2: B(2, 3)
z = 7x + 4y
⇒ z = 7(2) + 4(3)
⇒ z = 14 + 12
⇒ z = 26
Case 3: C(3, 0)
z = 7x + 4y
⇒ z = 7(3) + 4(0)
⇒ z = 21 + 0
⇒ z = 21
The value of z is maximum in the second case at point B(2, 3)
Hence, the unit of products A and B to be produced are 2 and 3 respectively, and the total maximum profit is Rs. 26
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