Q. 24.0( 7 Votes )
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Answer :
Let the three consecutive numbers be x, (x+1), (x+2).
Now according to the given criteria,
5 less than the sum of the number = x+(x+1)+(x+2)-5…..(i)
11 more than twice the second number = 2(x+1)+11…….(ii)
So from question equation (i) and equation (ii) are equal,
Hence
x+(x+1)+(x+2)-5 = 2(x+1)+11
⇒ 3x+3-5=2x+2+11
⇒ 3x-2=2x+13
⇒ 3x-2x=13+2
⇒ x=15
⇒ x+1=15+1=16
⇒ x+2=15+2=17
Hence the three consecutive numbers are
15, 16 and 17
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