Q. 15 Q3.8( 15 Votes )

Let’s find the ro

3(x-4)2+ 5(x-3)2 = (2x-5) (4x-1)-40

3(x2-8x+16)+5(x2-6x+9)=2x(4x-1)-5(4x-1)-40

3x2-24x+48+5x2-30x+45=8x2-2x-20x+5-40

8x2-54x+93=8x2-22x-35

93+35=54x-22x

32x=128 =4

This is the required root of the given equation.

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