Q. 24.0( 7 Votes )
Let’s write down
Answer :
Let the three consecutive numbers be x, (x+1), (x+2).
Now according to the given criteria,
5 less than the sum of the number = x+(x+1)+(x+2)-5…..(i)
11 more than twice the second number = 2(x+1)+11…….(ii)
So from question equation (i) and equation (ii) are equal,
Hence
x+(x+1)+(x+2)-5 = 2(x+1)+11
⇒ 3x+3-5=2x+2+11
⇒ 3x-2=2x+13
⇒ 3x-2x=13+2
⇒ x=15
⇒ x+1=15+1=16
⇒ x+2=15+2=17
Hence the three consecutive numbers are
15, 16 and 17
Rate this question :
How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Expertsview all courses
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
RELATED QUESTIONS :
Let’s find the ro
West Bengal - MathematicsLet’s find the ro
West Bengal - MathematicsSalem uncle of ou
West Bengal - MathematicsLet’s find the ro
West Bengal - MathematicsLet’s find the ro
West Bengal - MathematicsLet’s find the ro
West Bengal - MathematicsLet’s find the ro
West Bengal - MathematicsLet’s find the ro
West Bengal - MathematicsLet’s find the ro
West Bengal - MathematicsLet’s find the ro
West Bengal - Mathematics