Answer :
R.H.S = [(No. of terms in L.H.S) × (No. + 1) × (2 × No. + 1)]
(i) 12 + 22 + 32 + 42 + …… + 102 = [10 (10 + 1) × (2 × 10 + 1)]
= [2310]
= 385
(ii) 52 + 62 +….. + 122 = 12 + 22 + ….. 122 – (12 + 22 + 33 + 42)
= [12 × (12 + 1) × (2 × 12 + 1)] -
[4 ×(4 + 1) × (2 × 4 + 1)]
= 650 – 30
= 620
Rate this question :
How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
view all courses
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation


RELATED QUESTIONS :
If n is odd, then
RS Aggarwal - MathematicsObserve the follo
RD Sharma - MathematicsFind the value of
RS Aggarwal - MathematicsFind the value of
RS Aggarwal - MathematicsObserve the follo
RD Sharma - MathematicsWrite (T) for tru
RS Aggarwal - Mathematics