Q. 205.0( 6 Votes )

Ajita starts off

Answer :

Given that, Ajita goes to school at a uniform speed on her father’s scooter = 30km/h

Time taken to reach her school = 30 min =

Distance between her home and school = speed × time taken to reach


= 15 km

Distance = 15 KM

Distance covered by Ajita in 1 min = 1/2 km = 500m

The graph of the above situation is as follows


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