Answer :
Given that, Ajita goes to school at a uniform speed on her father’s scooter = 30km/h
Time taken to reach her school = 30 min =
Distance between her home and school = speed × time taken to reach
=
= 15 km
∴ Distance = 15 KM
∴ Distance covered by Ajita in 1 min = 1/2 km = 500m
The graph of the above situation is as follows
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