Answer :

Given that, Ajita goes to school at a uniform speed on her father’s scooter = 30km/h

Time taken to reach her school = 30 min =

Distance between her home and school = speed × time taken to reach

=

= 15 km

∴ Distance = 15 KM

∴ Distance covered by Ajita in 1 min = 1/2 km = 500m

The graph of the above situation is as follows

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