Answer :

Use of 15N in place of 35S in the original experiment would not give any conclusive result because:

1. 32P is radioactive and 15N is non-radioactive. So, it’s presence won’t be detected.

2. If hypothetically 15N would be radioactive, then it’s presence would be seen both inside the cell as it gets incorporated in the DNA as nitrogenous base and also as a supernatant as it gets incorporated in the amino group of amino acids.

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