Q. 184.0( 2 Votes )

Write the structu

Answer :


When CH3COOH is treated with ammonia, first it forms ammonium

salt, which upon heating lose a molecule of water to from acid

amide (CO—NH2 group)

Hence, A will be CH3CONH2

Now, CH3CONH2 (A) is treated with Br2/KOH, it gives a primary

amine which has one carbon less than the original amide.

Hence, B will be CH3—NH2

Now, CH3—NH2 (B) is treated with CHCl3 and alcoholic KOH, it gives

Isocyanides or carbylamines which have very unpleasant odour.

This reaction is called carbylamine reaction.

Hence, C will be CH3NC


When (arenediazonium fluoroborate) is treated with an

aqueous solution sodium nitrite(NaNO2) in the presence of Cu

powder, it forms Nitrobenzene by the removal of N2 and NaBF4.

Hence, A will be C6H5NO2

Now, C6H5NO2 (A) is treated with Fe and HCl, it gives aniline

Hence, B will be C6H5NH2

Now, C6H5NH2 (B) is treated with CH3COCl in the presence of

pyridine, it gives C6H5—NH—CO—CH3. This reaction is called

acetylation reaction.

Hence, C will be C6H5—NH—CO—CH3

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