Q. 184.0( 2 Votes )

Write the structu

Answer :

(a)


When CH3COOH is treated with ammonia, first it forms ammonium


salt, which upon heating lose a molecule of water to from acid


amide (CO—NH2 group)



Hence, A will be CH3CONH2


Now, CH3CONH2 (A) is treated with Br2/KOH, it gives a primary


amine which has one carbon less than the original amide.



Hence, B will be CH3—NH2


Now, CH3—NH2 (B) is treated with CHCl3 and alcoholic KOH, it gives


Isocyanides or carbylamines which have very unpleasant odour.


This reaction is called carbylamine reaction.



Hence, C will be CH3NC


(b)


When (arenediazonium fluoroborate) is treated with an


aqueous solution sodium nitrite(NaNO2) in the presence of Cu


powder, it forms Nitrobenzene by the removal of N2 and NaBF4.



Hence, A will be C6H5NO2


Now, C6H5NO2 (A) is treated with Fe and HCl, it gives aniline



Hence, B will be C6H5NH2


Now, C6H5NH2 (B) is treated with CH3COCl in the presence of


pyridine, it gives C6H5—NH—CO—CH3. This reaction is called


acetylation reaction.



Hence, C will be C6H5—NH—CO—CH3


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