When CH3COOH is treated with ammonia, first it forms ammonium
salt, which upon heating lose a molecule of water to from acid
amide (CO—NH2 group)
Hence, A will be CH3CONH2
Now, CH3CONH2 (A) is treated with Br2/KOH, it gives a primary
amine which has one carbon less than the original amide.
Hence, B will be CH3—NH2
Now, CH3—NH2 (B) is treated with CHCl3 and alcoholic KOH, it gives
Isocyanides or carbylamines which have very unpleasant odour.
This reaction is called carbylamine reaction.
Hence, C will be CH3NC
When (arenediazonium fluoroborate) is treated with an
aqueous solution sodium nitrite(NaNO2) in the presence of Cu
powder, it forms Nitrobenzene by the removal of N2 and NaBF4.
Hence, A will be C6H5NO2
Now, C6H5NO2 (A) is treated with Fe and HCl, it gives aniline
Hence, B will be C6H5NH2
Now, C6H5NH2 (B) is treated with CH3COCl in the presence of
pyridine, it gives C6H5—NH—CO—CH3. This reaction is called
Hence, C will be C6H5—NH—CO—CH3
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