Q. 195.0( 1 Vote )

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Answer :

a) Step 1: C6H5—COO-NH4+ C6H5 —CO--NH2 Benzamide (A)

Step 2:

(A) Aniline (B)

Step 3:


(B) acetanilide (C)

Thus, A is C6H5 —CO--NH2

B is C6H5—NH2

C is C6H5—NH—COCH3

b) Step 1: C6H5—N2+BF4- reacts with NaNO2 to form (A)

Step 2:

Nitrobenzene(A) Aniline (B)

Step 3:

Aniline(B) Carbylamine (C)
Note: The above reaction is carbylamine reaction.

In this reaction, primary aliphatic or aromatic amine is warmed with chloroform (CHCl3) and an alcoholic solution of KOH produce isocyanides or carbylamines which have very unpleasant odours

Thus, A is C6H5—NO2

B is C6H5—NH2

C is C6H5—NC

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(a) Write the reaChemistry - Board Papers