Answer :

Galvanic cell reaction: Zn(s)|Zn2+(aq)||Cu2+(aq)|Cu(s)

Anode- oxidation half-cell: Zn(s) Zn2+ (aq)+ 2e-

Cathode- reduction half-cell: Cu2+ (aq)+ 2e- Cu(s)

Overall reaction: Zn(s) + Cu2+ (aq) Zn2+(aq) +Cu(s)

Nernst equation:

Where, E cellis the electrode potential at any given concentration

E° cell is the standard electrode potential

R is the gas constant 8.314 JK-1mol-1

F is the Faraday constant (96500 C mol-1)

T is the temperature in Kelvin

[Zn2+] and [Cu2+] are the concentration of the Zn2+ and Cu2+ ion in the solution.

When we substitute the value for R, F and T(298K), we can reduce the equation to :

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