To write the IUPAC name of the given compound, we follow the steps given below:
⇒ Step 1: The longest carbon chain containing the OH group is selected as the parent chain and numbered in such a way that the carbon atom carrying the OH group gets the smallest number and then the carbon atom carrying the halogen atom gets the lowest possible number.
⇒ Step 2: As the second carbon contains the double bond (alkene) and there are total 4 carbons (butane) in the parent chain. Hence it will be named as but-2-en-1-ol
⇒ Step 3: As the second carbon also contains the halogen atom, i.e. Br. Hence, it will be named as 2-Bromo
⇒ Step 4: Now, third carbon contains a methyl group (CH3), hence it will be named as 3-methyl
Alphabetically, 2-Bromo comes first. Hence the final name of the compound is:
Rate this question :