Answer :
(i) Since three chloride ions are precipitated as AgCl, all the 6 molecules of water are present as ligand and chromium is the central metal. Therefore the formula of the compound is follows:
[Cr (H2O) 6]Cl3
(ii) Since two chloride ions are precipitated as AgCl, all the 5 molecules of water and one chlorine atom is present as ligand and chromium is the central metal. Therefore the formula of the compound is follows:
[Cr (H2O) 5 Cl]Cl2. (H2O)
(iii) Since one chloride ions are precipitated as AgCl, all the 4 molecules of water and two chlorine atom is present as ligand and chromium is the central metal. Therefore the formula of the compound is follows:
[Cr (H2O) 4 Cl2]Cl. (H2O) 2
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