Answer :

(i) Hydrogen + Chlorine → Hydrochloric Acid

The above reaction can be written as

H_{2} (g) +Cl_{2} (g)→ HCl (g)

So, we balance the equation by making the number of each element equal on both side and get,

**H _{2} (g) + Cl_{2} (g) → **

**2HCl (g)**

(ii) Barium chloride + Aluminium sulphate → Barium sulphate + Aluminium chloride

The above equation can be written as

BaCl

_{2}+ Al

_{2}(SO

_{4})

_{3}→ BaSO

_{4}+ AlCl

_{3}

So, after balancing we get,** 3BaCl _{2} (s) + Al_{2}(SO_{4})_{3} (s)**

**→**

**3BaSO**

_{4}(s) + 2AlCl_{3}(s)(iii) Na(s) + H

_{2}O (l) → NaOH (aq) + H

_{2}(g)

Balancing the equation and making the elements equal on both the side, we get:

**2Na + 2H**

_{2}O → 2NaOH + H_{2}Rate this question :

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