Answer :

a. The electronic configuration of the element (Z=17) is:


1s2 2s2 2p6 3s2 3p5


b. Period number = 7


As the element has 7 electrons in the outermost shell (3s2 3p5). Hence, it belongs to period 7.


c. Group number = 3


In the element (1s2 2s2 2p6 3s2 3p5), 3 is the highest principal quantum number. Hence, it belongs to third period.


d. Element family = p-block element


The element belongs to group 3 and period 7, this means it is located at the right side of the periodic table. Hence, it belongs to p-block family.


e. Valence electrons = 7


The element (1s2 2s2 2p6 3s2 3p5) has 7 valence electrons, i.e., electrons in the outermost shell (3s2 3p5).


f. Valency = 1


The valency is the number of electrons needed to complete the octet. So the element (2,8,7) need only one electron to achieve noble gas configuration (2,8,8)


g. Non-metal


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