Q. 234.6( 10 Votes )

Write balanced chemical equations for the following word equations:

(a) Calcium hydroxide + Carbon dioxide Calcium carbonate + Water

(b) Phosphorus pentachloride + Water Phosphoric acid + Hydrogen chloride

(c) Zinc + Silver nitrate Zinc nitrate + Silver

(d) Sodium + water sodium hydroxide + Hydrogen

(e) Aluminium + Copper chloride Aluminium chloride + Copper

Answer :

(a) The reaction is as follows:

Ca (OH)2 + CO2 CaCO3 + H2O


This reaction is a self-balanced reaction as number of molecules on reactant side is same as that on the product side.


(b) The reaction is as follows:


PCl5 + H2O H3PO4 + HCl


In this reaction there are five chlorine molecules on reactant side and only one molecule on the product side. So let us make the number of chlorine molecules 5 on product side also.


PCl5 + H2O H3PO4 + 5HCl


Now there are eight molecules of hydrogen on product side and only two molecules on reactant side. So the total balanced reaction is as follows:


PCl5 + 4H2O H3PO4 + HCl


(c) The reaction is as follows:


Zn + AgNO3 Zn (NO3)2 + Ag


In the above reaction there are two nitrate molecules on product side and only one nitrate molecule on reactant side. So let us first balance it.


Zn + 2AgNO3 Zn (NO3)2 + Ag


Now there two molecules of silver on reactant side and only one molecule on product side. So the total balanced equation is as follows:


Zn + 2AgNO3 Zn (NO3)2 + 2Ag


(d) The reaction is as follows:


Na + H2O NaOH + H2


In the above reaction there three molecules of hydrogen on product side and only two molecules on reactant side. Let us first make the number molecules of hydrogen on product side even in number.


Na + H2O 2NaOH + H2


Now there are two molecules of hydrogen on reactant side and four molecules on product side. So let us first balance it.


Na + 2H2O 2NaOH + H2


Now there two molecules of sodium on product side and only one molecule on reactant side. So the total balanced equation is as follows:


2Na + 2H2O 2NaOH + H2


(e) The reaction is as follows:


Al + CuCl2 AlCl3 + Cu


In the above reaction there are two molecules of chlorine on reactant side and three molecules of chlorine on product side. Let us first make the number of chlorine molecules even on product side.


Al + CuCl2 2AlCl3 + Cu


Now there are six molecules of chlorine on product side. So let us make it six molecules of chlorine on reactant side also.


Al + 3CuCl2 2AlCl3 + Cu


After making the chlorine molecules same on both sides, the number of copper molecule son product side is only one and on reactant side it is three. So let us make the number of copper molecules equal on both sides.


Al + 3CuCl2 2AlCl3 + 3Cu


Finally there two molecules of aluminium on product side and only one molecule on reactant side. So the total balanced equation can be written as follows:


2Al + 3CuCl2 2AlCl3 + 3Cu


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