Q. 11

Write an activity

Answer :

Take two test tubes. Mark them as ‘A’ and ‘B’. Take about 0.5 gm of sodium carbonate in the test tube ‘A’ and 0.5 gm of sodium hydrogen carbonate in test tube ‘B’. Add about 2 ml of dilute HCl acid to both test tubes. Pass the gas produced in each case through lime water as shown in the figure. Lime water in each case will turn milky due to the production of CO2 gas in each of the test tubes.



Reactions occurring in the above activity:


Tet tube ‘A’ Na2CO3 (s) + 2HCl (aq) 2Na2NaCl (aq) + CO2 (g) + H2O(l)


Test tube ‘B’ NaHCO3(s) + HCl (aq) NaCl (aq) + CO2(g) + H2O (l)


On passing the gas evolved through the lime water:



But on passing excess CO2 gas through the lime waster, milkiness disappears due to the formation of soluble CaHCO3



This activity shows that metal carbonates and metal hydrogen carbonates react with acids to form salt, CO2 and water.


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