Q. 95.0( 1 Vote )
Without using distance formula, show that points(-2, -1), (4, 0), (3, 3) and (-3, 2) are the vertices of a parallelogram.
Let the vertices be A(-2, -1), B(4, 0), C(3, 3), D(-3, 2)
Now mAB = =
mBC = = -3
mAD = = =
mAD = = -3
Now mAB = mCD ⇒ AB || CD
and mBC = mAD ⇒ BC || AD
Hence ABCD is a parallelogram.
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