Q. 745.0( 5 Votes )
With the help of a labelled diagram show that there are four octahedral voids per unit cell in a cubic close packed structure.
Answer :
In cubic close packing, each cube consists of eight small cubic components as shown in figure. Since atoms are present in corners and face centres, total atoms are:
Total atoms= atoms at face centres and atoms at corners
=8× (1/8) + 6× (1/2)=1+3 = 4
Total number of atoms = 4.
Now octahedral voids are present at Edge centres and body centre. (refer figure)
Total number of octahedral voids = 
Hence proved. 4 octahedral voids are present in cubic close packing.
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