• In the above question, molecule (A) is secondary halide and molecule (B) is a primary halide.
• We know that rate of SN1 reaction follows the order 3°>2°>1°.
• This means that a tertiary halide undergoes SN1 reaction more easily than a secondary halide.
• Thus molecule (B) undergoes SN1 reaction faster than molecule (A).
Rate this question :