Answer :

• In the above question, molecule (A) is secondary halide and molecule (B) is a primary halide.


• We know that rate of SN1 reaction follows the order 3°>2°>1°.


• This means that a tertiary halide undergoes SN1 reaction more easily than a secondary halide.


• Thus molecule (B) undergoes SN1 reaction faster than molecule (A).


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