Which of the following statements is correct?
A. Elements of group 15 form electron deficient hydrides.
B. All elements of group 14 form electron precise hydrides.
C. Electron precise hydrides have tetrahedral geometries.
D. Electron rich hydrides can act as Lewis acids.
An electron-precise hydride is a type of hydride which has the exact number of electrons required to form normal covalent bonds, no excess no deficient. These are formed generally by group 14 elements like Si and C which have 4 valence electrons.
Eg. CH4 , SiH4, etc.
Due to the sp3 hybridisation configuration, the molecular geometry is tetrahedral.
sp3 hybridisation is tetrahedral in geometry.
Tetrahedral geometries of CH4 and SiCl4.
B2H6 is an electron deficient hydride. These have an incomplete octet. They are formed generally by the group 13 elements like B, Al, etc.
Rate this question :