Q. 75.0( 4 Votes )

Which of the foll

Answer :

For 0.05 M Al2(SO4)3


Dissociation of Al2(SO4)3


Al2(SO4)3 2Al3+ + 3SO42-


i = 5


Where i is the actual no. of particles after dissociation


To find out the freezing point, we apply the formula:


ΔTf = i × concentration


As concentration = 0.05 M (given)


ΔTf = 5 × 0.05M


ΔTf = 0.25 moles of ions


For 0.1 M K3[Fe(CN)6]


Dissociation of K3[Fe(CN)6]


K3[Fe(CN)6] 3K+ + [Fe(CN)6]3-


i=3


Where i is the actual no. of particles after dissociation


To find out the freezing point, we apply the formula:


ΔTf = i × concentration


As concentration = 0.1 M (given)


ΔTf = 4 × 0.1M


ΔTf = 0.4 moles of ions


The higher the Tf value, the lower the freezing point. Hence, 0.05 M Al2(SO4)3 has higher freezing point.


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