Q. 24.0( 8 Votes )
Which of the following options does not represent ground state electronic configuration of an atom?
A. 1s2 2s2 2p6 3s2 3p6 3d8 4s2
B. 1s2 2s2 2p6 3s2 3p6 3d9 4s2
C. 1s2 2s2 2p6 3s2 3p6 3d10 4s1
D.1s2 2s2 2p6 3s2 3p6 3d5 4s1
o The filling up of electrons in corresponding orbitals decides the electronic stable ground state configuration of an atom and usually is determined by Aufbau principle (in the figure).
According to the principal “In the ground state of the atoms, the orbitals are filled according to the order of their increasing energies.” Which actually means that, lower energy orbitals get occupied by electrons before the higher ones; hence according to the effective nuclear charge and other several factors ( n , lvalue etc.) the order of energy goes like : 1s<2s<2p<3s<3p<4s<3d....so on... and for the first 3 options :(i) 1s2 2s2 2p6 3s2 3p6 3d8 4s2 (ii) 1s2 2s2 2p6 3s2 3p6 3d9 4s2
(iii) 1s2 2s2 2p6 3s2 3p6 3d10 4s1this order is maintained as we can see the 4s orbital is filled first (maximum capacity is 2 electrons ) and then the 3d (maximum capacity is 10 electrons)
o According to this, the electron should enter 4s orbital first and then to 3d orbital but in case of (iv) 1s2 2s2 2p6 3s2 3p6 3d5 4s1, this is a disparity to the rule hence cannot be considered as ground state electronic configuration of an atom. But it will be stable as 4s and 3d orbitals are almost the same in terms of inherent energy and d5 i.e. a half-filled orbital has generally attained a state of stability.
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