Answer :

Manganese (Z = 25) exhibits the largest number of oxidation states. This is because its electronic configuration is 3d54s2.


Because it has the maximum number of electrons (5 d electrons and 2s electrons) to easily lose and share.


Therefore, it can exhibit an oxidation state of +2 to +7.


The compounds are as follows:


Mn(0) as Mn(s), Mn(II) as MnO, Mn(II,III) , Mn etc.


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

When a chromite oChemistry - Exemplar

Give reasonChemistry - Board Papers