Q. 455.0( 6 Votes )

Which contains more molecules, 10 g of sulphur dioxide (SO2) or 10 g of oxygen (O2)?
(Atomic masses: S = 32 u; O = 16 u)

Answer :

Molar mass of SO2 = (32 + 2×16) g = 64g

Given mass of SO2 = 10g

1 mole of substance = 6.023 × 1023 particles of the substance

No. of moles of SO2 = 10g/64g = 0.15

Total no. of molecules of SO2 = 0.15 × 6.022 × 1023 = 0.90 × 1023 molecules of SO2

Molar mass of oxygen (O2) = 32g

Given mass of oxygen (O2) = 10g

1 mole of substance = 6.023 × 1023 particles of the substance

No. of moles of O2 = 10g/32g = 0.31

Total no. of molecules of O2 = 0.31 × 6.022 × 1023 = 1.88 × 1023 molecules of O2

Thus, 10g of O2 contains more no. of molecules.

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