Q. 125.0( 1 Vote )

# When we heat an o

1. We know that,

Work done = force ×displacement

Volume = area ×displacement

Therefore,

Work done=pressure ×volume

Let change in the volume of object = ΔV = V2-V1

Pressure =P

Thus, work done by the object W

W=PΔV

During expansion volume increases. Hence work done will be positive and equals PΔV.

2. According to First law of thermodynamics,

ΔQ=ΔU+ΔW

Where ΔQ=heat supplied to the system

ΔU=change in internal energy

ΔW=work done by the system

Since work done by the gas is not zero, heat supplied to the object will not be equal to internal energy only.

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