Answer :

1. We know that,


Work done = force ×displacement



Volume = area ×displacement


Therefore,


Work done=pressure ×volume


Let change in the volume of object = ΔV = V2-V1


Pressure =P


Thus, work done by the object W


W=PΔV


During expansion volume increases. Hence work done will be positive and equals PΔV.


2. According to First law of thermodynamics,


ΔQ=ΔU+ΔW


Where ΔQ=heat supplied to the system


ΔU=change in internal energy


ΔW=work done by the system


Since work done by the gas is not zero, heat supplied to the object will not be equal to internal energy only.


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