Answer :

A=MnO2, B=K2MnO4, C= KMnO4, D= KIO3

When Manganese dioxide(A) is fused with KOH, it gives a green solution of potassium manganate(B).

2MnO2 (A) + 4KOH +O2 2K2MnO4(B) +2H2O

Potassium manganate disproportionates to give purple potassium permanganate(C).

3MnO42- +H+2MnO4-(C)+MnO2 +2H2O

Potassium permanganate on reacting with KI gives potassium iodate(D) and manganese dioxide again

2MnO4- +H2O +KI 2MnO2 + 2OH- + KIO3(D)

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses

<span lang="EN-USChemistry - Board Papers

<span lang="EN-USChemistry - Board Papers

When an oxide of Chemistry - Exemplar

Identify compoundChemistry - Exemplar

A violet compoundChemistry - Exemplar