Answer :

Given


Heat absorbed in process abc ΔQ1=80J


Work done by the system in process abc ΔW1=30J


Work done by the system in process adc ΔW2=10J


Let heat absorbed into the system during process adc =ΔQ2


Now initial point a and final point c is the same for both the processes is the same. So, change in internal energy will be the same for both the process, as internal energy is a state function independent of the path taken.


Therefore,


ΔU1=ΔU2=ΔU ……(i)


From first law of thermodynamics, we know that,


ΔQ=ΔU+ΔW


Where ΔQ=heat supplied to the system


ΔU=change in internal energy


ΔW=work done by the system


Using first law of thermodynamics for process abc


ΔQ1=ΔU1+ΔW1


ΔU1=ΔQ1-ΔW1=80-30=50J


Using first law of thermodynamics for process adc


ΔQ2=ΔU2+ΔW2


=ΔU1+ΔW2 (from (i))


= 50+10=60J


heat absorbed into the system during process adc= 60J.


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