Q. 85.0( 1 Vote )

# When a system is taken through the process abc shown in figure 80J of heat is absorbed by the system and 30 J of work is done by it. If the system does 10 J of work during the process adc, how much heat flows into it during the process?

Given

Heat absorbed in process abc ΔQ1=80J

Work done by the system in process abc ΔW1=30J

Work done by the system in process adc ΔW2=10J

Let heat absorbed into the system during process adc =ΔQ2

Now initial point a and final point c is the same for both the processes is the same. So, change in internal energy will be the same for both the process, as internal energy is a state function independent of the path taken.

Therefore,

ΔU1=ΔU2=ΔU ……(i)

From first law of thermodynamics, we know that,

ΔQ=ΔU+ΔW

Where ΔQ=heat supplied to the system

ΔU=change in internal energy

ΔW=work done by the system

Using first law of thermodynamics for process abc

ΔQ1=ΔU1+ΔW1

ΔU1=ΔQ1-ΔW1=80-30=50J

Using first law of thermodynamics for process adc

ΔQ2=ΔU2+ΔW2

=ΔU1+ΔW2 (from (i))

= 50+10=60J

heat absorbed into the system during process adc= 60J.

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