Q. 63.9( 12 Votes )
When a proton is released from rest in a room, it starts with an initial acceleration a0 towards west. When it is projected towards north with a sped v0, it moves with an initial acceleration 3a0 towards west. Find the electric field and the minimum possible magnetic field in the room.
Answer :
Given-
Proton is released from rest in a room, it starts with an initial acceleration a0 towards west
Now, we know coulomb’s force F given by –
where
q = charge
E= electric field
Also,
And Newton's second law of motion
Where
m = mass
a= acceleration
From (1) and (2)
Electric field,
which acts towards west.
We know, Lorentz force F is given by -
where,
q = charge
v = velocity of the charge
B=magnetic field
and
and θ = the angle between B and l
Now, given that when the proton is projected towards north with a speed v0, it moves with an initial acceleration 3a0 towards west.
An electric force will act on the proton in the west direction, which produces an acceleration a0 on the proton.
Initially the proton was moving with velocity v, so a magnetic force was also acting on the proton.
So, magnetic force acting will be the only cause behind the change in acceleration of the proton
Change in acceleration towards west due to the magnetic force acting on it is -
∆a = 3a0 − a0 = 2a0
So from (2), the force will become -
Hence, required magnetic field
Rate this question :
Equation of electric and magnetic field52 mins
Magnetic force on moving charge particle in magnetic field | Quiz32 mins
Magnetic force on moving charge particle in magnetic field44 mins
Magnetic field due to current carrying straight wire37 mins
Magnetic field due to current carrying circular loop36 mins
Superfast Revision of Potential & Potenial Energy (Theory + Interactive Quiz)47 mins
Few Applications of Gauss's law54 mins
Electric field inside cavity37 mins
Gain Confidence on Magnetic Effects of Current with Questions41 mins
Test Your Knowledge of Electric Charge & Coulomb's Law47 mins
A rectangular coil of 100 turns has length 5 cm and width 4 cm. It is placed with its plane parallel to a uniform magnetic field and a current of 2A is sent through the coil. Find the magnitude of the magnetic field B, if the torque acting on the coil is 0.2 N m–1.
HC Verma - Concepts of Physics Part 2A circular coil of radius 2.0 cm ahs 500 turns in it and carries a current of 1.0 A. Its axis makes an angle of 30° with the uniform magnetic field of magnitude 0.40 T that exist in the space. Find the torque acting on the coil.
HC Verma - Concepts of Physics Part 2A rectangular loop of sides 20 cm and 10 cm carries a current of 5.0 A. A uniform magnetic field of magnitude 0.20 T exists parallel to the longer side of the loop.
(a) What is the force acting on the loop?
(b) What is the torque acting on the loop?
HC Verma - Concepts of Physics Part 2
A circular loop carrying a current i has wire of total length L. A uniform magnetic field B exists parallel to the plane of the loop.
(a) Find the torque on the loop.
(b) If the same length of the wire is used to form a square loop, what would be the torque? Which is larger?
HC Verma - Concepts of Physics Part 2
Fe+ions are acceleration through a potential difference of 500 V and are injected normally into a homogeneous magnetic field B of strength 20.0 mT. Find the radius of the circular paths followed by the isotopes with mass numbers 57 and 58. Take the mass of an ion = A(1.6 × 10–27) kg where A is the mass number.
HC Verma - Concepts of Physics Part 2A charged particle moves along a circle under the action of possible constant electric and magnetic fields. Which of the following are possible?
HC Verma - Concepts of Physics Part 2A charged particle moves in a gravity-free space without change in velocity. Which of the following is/are possible?
HC Verma - Concepts of Physics Part 2If a charged particle at rest experiences no electromagnetic force,
HC Verma - Concepts of Physics Part 2If a charged particle goes unaccelerated in a region containing electric and magnetic fields.
HC Verma - Concepts of Physics Part 2