Answer :

A is FeCr2O4, B is Na2CrO4, C is Na2Cr2O7.2H2O and D is K2Cr2O7.


The reactions are


1.


2.


3.


Thus, A is chromite of iron which when reacts with the sodium carbonate gives a yellow solution (Na2CrO4), which in the presence of the H+ ion (acid) gives compound C (Na2Cr2O7.2H2O) which on treatment with KCl solution gives orange crystal of K2Cr2O7.


OR


A is MnO2, B is K2MnO4, C is KMnO4 and D is KIO3.


The reaction involved is


1.


2.


3.


Thus, the reaction involves these steps and their yields are respectively given.


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