Answer :

A=FeCr2O4, B=Na2CrO4, C=Na2Cr2O7.2H2O, D= K2Cr2O7


Explanation:


When a chromite ore is fused with sodium carbonate, a yellow solution of sodium chromate is formed


4FeCr2O4(A) 8Na2CO3+ 7O2 8Na2CrO4(B) + 2Fe2O3+8CO2


When this yellow solution of sodium chromate is treated with acid, it changes to sodium dichromate


2NaCrO4 +2H+ Na2Cr2O7 (C)+2Na+ +H2O


Sodium dichromate on treatment with KCl gives orange crystals of potassium dichromate


Na2Cr2O7 +2KCl K2Cr2O7 (D)+2NaCl


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