Q. 275.0( 1 Vote )

When a (60 W, 220V) bulb and a (100 W, 220 V) bulb are connected in series, then which bulb will glow brighter?

OR

In a voltmeter, there are 20 divisions between the 0 mark and 0.5 V mark. Calculate the least count of the voltmeter.

Answer :

By knowing the resistance of each bulb, we can know that which bulb will glow brighter. Higher the resistance, brighter the bulb will glow.


I case: Bulb A (60 W, 220V)


Given: Power = 60W


Voltage = 220V


To calculate the resistance by the formula V = IR, first, we need to find out the current flowing in the bulb. Apply the formula:


P = VI




• I = 0.27A


Now apply the formula:


V = IR




• R = 814.8 ohm


Thus, the resistance of the bulb A is 814.8 ohm.


II case: Bulb B (100 W, 220V)


Given: Power = 100W


Voltage = 220V


To calculate the resistance by the formula V = IR, first, we need to find out the current flowing in the bulb. Apply the formula:


P = VI




• I = 0.45A


Now apply the formula:


V = IR




• R = 488.8 ohm


Thus, the resistance of the bulb B is 488.8 ohm.


The resistance of the bulb A is higher. Hence it will glow more brighter than bulb B.


OR


It is given that in a voltmeter there are 20 divisions between the 0 mark and 0.5 V mark.


Given: Number of divisions = 20


Distance between the two marks = 0.5V – 0V = 0.5V


We need to find out the least count of a voltmeter.


Least count: The smallest measured value of any instrument is said to be the least count of that instrument. It is measured as:




• Least count of voltmeter = 0.025V


Thus, the least count of the given voltmeter is 0.025V.


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