Q. 23.8( 231 Votes )

When 3.0 g

Answer :

Answer will be governed by the law of constant proportions which states that the mass of reactant must be equal to the mass of the product formed during a reaction

Now, since carbon and oxygen combine in the fixed proportion of 3 : 8 by mass to produce 11 g of carbon dioxide,

   3    +   8    =   11 (by ratio proportion)

According to the question, the equation formed will be:-

3    +  50      =   11         +   42   
    53            =            53

Therefore, the same mass of carbon dioxide (11 g) will be obtained even if we burn 3 g of carbon in 50 g of oxygen.
The extra oxygen (50 – 8 = 42 g oxygen) will remain unchanged.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses

Which postulate oLakhmir Singh & Manjit Kaur - Chemistry

A liquid compoundLakhmir Singh & Manjit Kaur - Chemistry

One of the forms Lakhmir Singh & Manjit Kaur - Chemistry