Answer will be governed by the law of constant proportions which states that the mass of reactant must be equal to the mass of the product formed during a reaction
Now, since carbon and oxygen combine in the fixed proportion of 3 : 8 by mass to produce 11 g of carbon dioxide,
3 + 8 = 11 (by ratio proportion)
According to the question, the equation formed will be:-
3 + 50 = 11 + 42
53 = 53
Therefore, the same mass of carbon dioxide (11 g) will be obtained even if we burn 3 g of carbon in 50 g of oxygen.
The extra oxygen (50 – 8 = 42 g oxygen) will remain unchanged.
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