When 1.0 × 10<sup

Given:

n=1.0 × 10¹²

V= 10 V

Formula used:

1. Charge can be given by the formula

Where Q→ Charge on the capacitor

n → number of the electrons

e → electric charge of an electron =

2. The capacitance of a parallel plate Capacitor is given by

Where Q → charge on the capacitor

V → Voltage or potential difference

Putting the values in the formula 1, we get

Substitute Q and C in Formula 2), we get

Thus, the capacitance of the parallel plate capacitor is

So, if 1.0 × 10¹² electrons are transferred between two conductors the capacitance of the parallel plate capacitor is F when a potential difference is 10V