Q. 35.0( 1 Vote )

When 0.1 mol CoCl3(NH3)5 is treated with excess of AgNO3, 0.2 mol of AgCl are obtained. The conductivity of solution will correspond to
A. 1:3 electrolyte

B. 1:2 electrolyte

C. 1:1 electrolyte

D. 3:1 electrolyte

Answer :

When 0.1 mole of CoCl3(NH3)5 was reacted with excess of AgNO3, we get 0.2 moles of AgCl. So, there are two chloride ions that are free and not part of the complex. The formula for complex has to be [Co(NH3)5Cl]Cl2.

[Co(NH3)5Cl]Cl2[Co(NH3)5Cl]+ + 2Cl-

Therefore, the conductivity of the solution will be 1:2 electrolyte

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