Q. 31 B4.7( 18 Votes )

What weight of each element is present in 1.5 moles of sodium sulphite, Na2SO3?

(Atomic masses: Na = 23 u; S = 32 u; O = 16 u)

Answer :

1.5 moles of Na2SO3 has 1.5×2 = 3 moles of Na

1.5 moles of Na2SO3 has 1.5×1 = 1.5 mole of S


1.5 moles of Na2SO3 has 1.5×3 = 4.5 moles of O.


As we know that Mass of an element= number of moles x atomic mass


Thus, mass of sodium = 3 × 23 g = 69g


Mass of sulphur = 1.5 × 32 = 48g


Mass of oxygen = 4.5 × 16 g = 72g


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