Given, V = 2L and Molarity = 5M
We know that Molar mass of H2O2 = 34g
Molarity (M) =
Therefore, mass of hydrogen peroxide will be present in 2 litres of a 5 molar solution is 340g.
Mass of oxygen which will be liberated by the decomposition of 200 mL of this solution can be calculated as shown below.
No. of moles =
Molar volume = volume at STP = 22.4 L or 22400ml
No. of moles = = 0.0089
2H2O2 → 2H2O + O2
From the above equation it is clear that,
2 moles of H2O2 → 1 mole of O2
0.0089 moles of H2O2 → moles of O2
Now, we know mass = no. of moles of O2 × molecular mass of O2
= = 0.15g
Mass of oxygen which will be liberated by the decomposition of 200 mL of this solution is 0.15g.
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