Q. 12 B3.8( 44 Votes )

What is the force of repulsion if each sphere is charged double the above amount, and the distance between them is halved?

Answer :

Force if charges on each sphere is doubled and the distance is halved.


Given:


Q1 = 2 × q


Q2 = 2 × q


R = 0.5 × r


Using Coulomb’s law, we get,


…(1)



Where, ε0 is the permittivity of the free space.




F = 0.243 N


The mutual force is 0.243N and it is repulsive in nature.


The new force is found to be 16 times the force in case I.


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