What is the

Force if charges on each sphere is doubled and the distance is halved.

Given:

Q₁ = 2 × q

Q₂ = 2 × q

R = 0.5 × r

Using Coulomb’s law, we get,

…(1)

Where, ε₀ is the permittivity of the free space.

⇒

⇒

⇒ F = 0.243 N

The mutual force is 0.243N and it is repulsive in nature.

The new force is found to be 16 times the force in case I.