Q. 12 B3.8( 44 Votes )

# What is the force of repulsion if each sphere is charged double the above amount, and the distance between them is halved?

Answer :

Force if charges on each sphere is doubled and the distance is halved.

Given:

Q_{1} = 2 × q

Q_{2} = 2 × q

R = 0.5 × r

Using Coulomb’s law, we get,

…(1)

Where, ε_{0} is the permittivity of the free space.

⇒

⇒

⇒ F = 0.243 N

The mutual force is 0.243N and it is repulsive in nature.

The new force is found to be 16 times the force in case I.

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PREVIOUSTwo insulated charged copper spheres A and B have their centres separated by a distance of 50 cm. What is the mutual force of electrostatic repulsion if the charge on each is 6.5 × 10–7 C? The radii of A and B are negligible compared to the distance of separation.NEXTSuppose the spheres A and B in Exercise 1.12 have identical sizes. A third sphere of the same size but uncharged is brought in contact with the first, then brought in contact with the second, and finally removed from both. What is the new force of repulsion between A and B?

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