The coulomb attraction formula used to find the force, F is given as,
Where, q1 and q2 are the charges.
r is the distance between the charges.
is a constant and its value is 9x109 N m2 C-2
ϵ0 is the permittivity of free space. Its value is 8.85 x 10-12 (F/m)
Now, the diagram is:
Since, both the charges are positive, thus, the nature of force will be repulsive. F12 is the force on charge q2 caused by charge q1 and F21 is the force on charge 1 due to charge 2 .
Charge on the first sphere, q1 = 2 × 10–7 C
Charge on the second sphere, q2 = 3 × 10–7 C
Distance between the spheres, r(in m) =30/100=0.3 m
Putting the values in equation (1), we get,
F = 6 × 10-3 N
Hence, the force between the given charged particles will be 6 × 10-3 N. Since the nature of the charges is the same i.e. they are both positive. Hence, the force will be repulsive.
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