Answer :

The coulomb attraction formula used to find the force, F is given as,

…(1)

Where, q_{1} and q_{2} are the charges.

r is the distance between the charges.

is a constant and its value is 9x10^{9} N m^{2} C^{-2}

ϵ_{0} is the permittivity of free space. Its value is 8.85 x 10^{-12} (F/m)

Now, the diagram is:

Since, both the charges are positive, thus, the nature of force will be repulsive. F_{12} is the force on charge q2 caused by charge q1 and_{ }F_{21} is the force on charge 1 due to charge 2 _{.}

Now, Given:

Charge on the first sphere, q_{1} = 2 × 10^{–7} C

Charge on the second sphere, q_{2} = 3 × 10^{–7} C

Distance between the spheres, r(in m) =30/100=0.3 m

Putting the values in equation (1), we get,

F = 6 × 10^{-3} N

Hence, the force between the given charged particles will be 6 × 10^{-3} N. Since the nature of the charges is the same i.e. they are both positive. Hence, the force will be repulsive.

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