Q. 20

# What is the exces

Excess pressure inside the soap bubble: Excess pressure inside the air bubble: Where,

S is the surface tension of the soap solution.

r is the radius of the soap bubble.

r’ is the radius of the air bubble.

Total Pressure inside the air bubble at a depth of 0.4 m= P1

P1 = P0 + hρg + P’

Where,

‘P0’ is the atmospheric pressure

Given,

Radius of the soap bubble, r = 5.0 mm = 5 × 10-3 m

Surface tension of the soap solution, S = 2.50 × 10-2 N / m

Relative density to the air of the soap solution, ρ = 1.2 × 103 kg /m3

The height at which the air bubble is formed, h = 40 cm = 0.4 m

Radius of the air bubble, r’ = r = 5 × 10-3 m

Acceleration due to gravity = 9.8 m/s2

The atmospheric pressure, P0 = 1.01 × 105 Pa

Therefore,

Excess pressure inside the soap bubble P = 20 Pa

Excess pressure inside the air bubble, P’ = 10 Pa

The total pressure inside an air bubble at the depth of 0.4 m, P1

P1 = 1.01 × 105 Pa + (0.4 m × 1.2 × 103 kg/m3 × 9.8 m/s2 ) + 10 Pa

P1 = 1.057 × 105 Pa

The excess pressure inside the soap bubble is 20 Pa, the excess pressure inside the air bubble 10 Pa and the total pressure inside the air bubble is 1.057 × 105 Pa

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation view all courses RELATED QUESTIONS :

The surface tensiPhysics - Exemplar

Surface tension iPhysics - Exemplar

A hot air balloonPhysics - Exemplar

If a drop of liquPhysics - Exemplar

For a surface molPhysics - Exemplar

The capillaries sHC Verma - Concepts of Physics Part 1

The free surface Physics - Exemplar

Consider a small HC Verma - Concepts of Physics Part 1

Find the excess pHC Verma - Concepts of Physics Part 1

A 5.0 cm long strHC Verma - Concepts of Physics Part 1