# What is the equilibrium concentration of each of the substances in the equilibrium when the initial concentration of ICl was 0.78 M?2ICl (g) ⇌ I2 (g) + Cl2 (g); Kc= 0.14

For the given reaction, let’s assume that the molar concentration of I2 and Cl2 at equilibrium is x mol/L.

The given reaction is

2ICl (g) I2 (g) + Cl2 (g)

Initial concentration 0.78M 0 0

Equilibrium concentration (0.78-2x)M x x

Equilibrium constant (Kc) is defined as a number that expresses the relationship between the amounts of products and reactants present at equilibrium in a reversible chemical reaction at a given temperature.

Here, Kc = 0.14

For the given reaction, Where, [I2]=concentration of I2 in mol/L at equilibrium

[Cl2]=concentration of Cl2 in mol/L at equilibrium

[ICl]=concentration of ICl in mol/L at equilibrium   X = 1.67

Therefore, at equilibrium,

[H2]=[I2]=0.167 M

[ICl]= 0.78 - (2x0.167) = 0.446 M

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