What is the</

Here we are given kinetic energy of electron

K = 120 eV

We know 1 eV = 1.6 × 10-19 J

i.e. kinetic Energy ,K = 120 × 1.6 × 10-19 J = 1.92 × 10-17J

(a) We know kinetic energy of a particle is given by the relation

Where K is the kinetic energy of a particle of mass m moving with speed v

Now multiplying L.H.S. and R.H.S. of the equation by m we get

or

But we know momentum is given by relation, p = mv

So, substituting we get

or

i.e. p = √2mK

Or we can say momentum P of any particle can be expressed in terms of its mass m and kinetic energy K as

p = √2mK

Particle is electron so we have mass of electron

m = 9.1 × 10-31Kg

kinetic energy of particle

K = 1.92 × 10-17J

Putting the values in equation we get

= 5.91 × 10-24 Kgms-1

So we get momentum of electron is 5.91 × 10-24 Kgms-1

(b) But we know momentum is given by relation

P = mv

Where P is momentum of particle of mass m moving with speed v

So we get speed of electron is

v = P/m

here the momentum of electron

P = 5.91 × 10-24 Kgms-1

Mass of electron

m = 9.1 × 10-31Kg

so putting these values we get the speed of electron as

or we can say speed of electron is 6.5 × 106 ms-1

(c) Now we know de Broglie wavelength of a Particle is given by relation

𝜆 = h/mv

Where 𝜆 is de Broglie wavelength of the particle having mass m and moving with velocity v and h is Planck’s constant

But we know momentum is given by relation

P = mv

Where P is the momentum of particle having mass m and moving with velocity v

So substituting we get de Broglie wavelength of Particle as

𝜆 = h/P

value of Planck’s constant

h = 6.6 × 10-34Js

and momentum of electron is

P = 5.91 × 10-24 Kgms-1

Putting these values we get

= 0.112 nm

So the wavelength of the electron is 0.112 nm

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