Answer :

The van’t Hoff factor for strong electrolyte is:


i = Total number of ions after dissociation/association/Total number of ions before dissociation/association.


For NaCl, the van’t Hoff factor is 2 as it dissociates into two ions i.e.



Van’t Hoff factor is independent of the molality of solute added.


Thus, iA = iB = iC .


Thus, Option (iii) is the correct answer.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

A statement of asChemistry - Exemplar

Match the laws giChemistry - Exemplar